The Greatest Number Of 4 Digits Which Is Divisible By Each One Of The Number 12,18,21 And 28 Is? Greatest Number Of 4 Digits Is 9999 (2023)

1. The greatest 4 digit number which is exactly divisible by each - Examveda

Solution(By Examveda Team). The greatest 4 digits number is 9999. The LCM of 12, 18, 21, 28 is 252. On dividing 9999 by 252 the remainder comes out to 171
The greatest 4 digit number which is exactly divisible by each one of the numbers 12, 18, 21 and 28 = ? a) 9288 b) 9882 c) 9828 d) 9928

Required number is divisible by the L . C . M of 12, 18, 21, 28 i.e 252. ... ∴ Required number = (9999 - 171) = 9828.
The greatest number of four digits which is divisible by each one of the numbers 12, 18 21 and 28 is ?

12 = 1 × 2 × 2 × 3 = 22 × 31. LCM of 18 and 12 = 22 × 32 = 36. Largest 4-digit number is 9999. Now, if we divide 9999 by 36, we will get 277.75 as quotient.
The greatest four digit number which when divided by 18 and 12 leaves a remainder of 4 in each case isa 9976b 9940c 9904d 9868

The greatest four digit number =9999 we can get the required number by following steps: step 1 : Divide 9999 by LCM of 15,24 and 36
Click here👆to get an answer to your question ✍️ Find the greatest number of four digits which is exactly divisible by 15, 24 and 36.

number 12, 18, 21 and 28 is. A) 9830. B) 9828. C) 9821. D) 9825. Explanation: Greatest number of 4 digits is 9999. L.C.M of 12, 18, 21, 28 = 252. on dividing ...
The greatest number of 4 digits which is divisible by each one of the
number 12, 18, 21 and 28 is, LCM And HCF questions, Aptitude questions, india

Answer with Explanation.Aptitude - Quiz Day-14 The greatest number of 4 digits which is divisible by each one of the number 12,18,21 and 28 is .
Answer with Explanation.Aptitude - Quiz Day-14 The greatest number of 4 digits which is divisible by each one of the number 12,18,21 and 28 is .Greatest number of 4 digits is 9999 L.C.M

Solution: The greatest 4 digits number is 9999 The LCM of 12, 18, 21, 28 is 252 On dividing 9999 by 252 the remainder comes out to 171 Required number ...
Solution: The greatest 4 digits number is 9999 The LCM of 12, 18, 21, 28 is 252 On dividing 9999 by 252 the remainder comes out to 171 Required number = 9999 - 171 = 9828

Step by step video, text & image solution for The greatest four digit number which is exactly divisible by each one of the numbers 12, 18, 21 and 28. by ...
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